CodingBat Java Solutions 2 - Array1

<div dir="ltr" style="text-align: left;" trbidi="on"> <div class="separator" style="clear: both; text-align: center;"> <a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhe8_EUGExRg-wM7-1IOop02ErQ0q7uJ1oUHrX40udEhSWjpGy18diQtw3AbORIusyaYACHZ3Y8HcH0HnxOj28DrpntP5Yf-99afdUGeu_0CNiNTh2KXTa_8P4iBEb1F-ZWH_FXqhFwyXg/s1600/Java.jpeg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="266" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhe8_EUGExRg-wM7-1IOop02ErQ0q7uJ1oUHrX40udEhSWjpGy18diQtw3AbORIusyaYACHZ3Y8HcH0HnxOj28DrpntP5Yf-99afdUGeu_0CNiNTh2KXTa_8P4iBEb1F-ZWH_FXqhFwyXg/s320/Java.jpeg" width="320" /></a></div> <b>Given an array of ints length 3, return a new array with the elements in reverse order, so {1, 2, 3} becomes {3, 2, 1}. </b><br /> <b>reverse3({1, 2, 3}) → {3, 2, 1}</b><br /> <b>reverse3({5, 11, 9}) → {9, 11, 5}</b><br /> <b>reverse3({7, 0, 0}) → {0, 0, 7}</b><br /> <br /> <h4 style="text-align: left;"> Solution:</h4> <br /> public int[] reverse3(int[] nums) {<br />   int[] rev={nums[2],nums[1],nums[0]};<br />   return rev;<br /> }<br /> <div> <br /></div> </div>

HOME Java CodingBat Java Solutions 2 - Array1

Given an array of ints length 3, return a new array with the elements in reverse order, so {1, 2, 3} becomes {3, 2, 1}.  reverse3({1, 2,...

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CodingBat Java Solutions - Array1

<div dir="ltr" style="text-align: left;" trbidi="on"> <b><br /></b> <b><br /></b> <b><br /></b> <br /> <div class="separator" style="clear: both; text-align: center;"> <a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh_7sUVZ87plKcmhryj4m3qzGq9pq-iMdiD1YFsCaJFpDPtf3x9SEDygFAovxSA0lloT3uem72XNoHk2FFJj-f1qN69oBC9PTfjLTka2zEONWhOwXf5zwgPQp72wC9QAzw-NBLFUHNEaAE/s1600/Java.jpeg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="266" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh_7sUVZ87plKcmhryj4m3qzGq9pq-iMdiD1YFsCaJFpDPtf3x9SEDygFAovxSA0lloT3uem72XNoHk2FFJj-f1qN69oBC9PTfjLTka2zEONWhOwXf5zwgPQp72wC9QAzw-NBLFUHNEaAE/s320/Java.jpeg" width="320" /></a></div> <b><br /></b> <b><br /></b><b>Given an array of ints length 3, figure out which is larger between the first and last elements in the array, and set all the other elements to be that value. Return the changed array. </b><br /> <b>maxEnd3({1, 2, 3}) → {3, 3, 3}</b><br /> <b>maxEnd3({11, 5, 9}) → {11, 11, 11}</b><br /> <b>maxEnd3({2, 11, 3}) → {3, 3, 3}</b><br /> <br /> <h3 style="text-align: left;"> Solution:</h3> public int[] maxEnd3(int[] nums) {<br />   int max = Math.max(nums[0], nums[2]);<br />   nums[0] = max;<br />   nums[1] = max;<br />   nums[2] = max;<br />   return nums;<br /> <br />   // Solution notes: you could write if-logic to figure out<br />   // which element is the biggest, but here we use Math.max()<br />   // to solve that part nicely.<br /> }<br /> <br /> <h3 style="text-align: left;"> OR</h3> <br /> public int[] maxEnd3(int[] nums) {<br />   int[] maxVal=new int[3];<br />   maxVal[0]=nums[0];<br />   if(nums[2] >= maxVal[0])<br />   maxVal[0] = nums[2];<br />   maxVal[1] = maxVal[0];<br />   maxVal[2] = maxVal[0];<br />   return maxVal;<br /> }<br /> <div> <br /></div> </div>

HOME Java CodingBat Java Solutions - Array1

Given an array of ints length 3, figure out which is larger between the first and last elements in the array, and set all the other ...

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